0=34.3t-16t^2

Solution for 0=34.3t-16t^2 equation:

0=34.3t-16t^2

We move all terms to the left:

0-(34.3t-16t^2)=0

We add all the numbers together, and all the variables

-(34.3t-16t^2)=0

We get rid of parentheses

16t^2-34.3t=0

a = 16; b = -34.3; c = 0;
Δ = b2-4ac
Δ = -34.32-4·16·0
Δ = 1176.49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34.3)-\sqrt{1176.49}}{2*16}=\frac{34.3-\sqrt{1176.49}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34.3)+\sqrt{1176.49}}{2*16}=\frac{34.3+\sqrt{1176.49}}{32}
$